Answer:
The solution is B
Step-by-step explanation:
[tex]x + 5 \geqslant 1 \\ x \geqslant 1 - 5 \\ x \geqslant - 4[/tex]
then:
[tex]x - 7 < - 3 \\ x < - 3 + 7 \\ x < 4[/tex]
therefore, interval [limits] of x:
[tex] - 4 \leqslant x < 4[/tex]
