Answer:
[tex] \frac{6 {x}^{2}y - 12 {x}^{4} y + 15 {x}^{3} {y}^{2} - 3 {x}^{2} {y}^{2} }{3 {x}^{2}y } \\ \frac{2 \times 3 {x}^{2}y - 6 {x}^{2} 3 {x}^{2} y + 5xy3 {x}^{2} y - y3 {x}^{2} y}{3 {x}^{2}y } \\ cancel3 {x}^{2} y \: from \: all \: term \\ = \frac{2 - 6 {x}^{2} + 5x y - y }{1} \\ = 2 - 6 {x}^{2} + 5xy - y \\ thank \: you[/tex]
