Answer:
[tex]P=\frac{1}{2}[/tex]
Step-by-step explanation:
[tex]P=\frac{(x+3)^2-(x-3)^2}{(x+6)^2-(x-6)^2}[/tex]
[tex]=\frac{[(x+3)-(x-3)][(x+3)+(x-3)]}{[(x+6)-(x-6)][(x+6)+(x-6)]}[/tex]
[tex]=\frac{6(2x)}{12(2x)}[/tex]
[tex]=\frac{1}{2}[/tex]
Por tanto, el valor de P será [tex]\frac{1}{2}[/tex]
