Answer:
[tex]-\frac{10}{3}<x<2\:[/tex]
Step-by-step explanation:
Rewrite in standard form: [tex]3x^2+4x-20<0[/tex]
Factor: [tex]\left(x-2\right)\left(3x+10\right)<0[/tex]
Solve individually for x:
[tex]x-2<0\\x<2[/tex]
[tex]3x+10<0\\3x<-10\\x<\frac{-10}{3}[/tex]
Combine:
[tex]-\frac{10}{3}<x<2\:[/tex]
