Answer:
x = 3 + [tex]\sqrt{3}[/tex] , 3 - [tex]\sqrt{3}[/tex]
Step-by-step explanation:
(2x-3)(x-2) + (x9x-2) = (x)(2x-3)
(2x-3)(x-2)+x(x-2)=x(2x-3)
(2x-3)(x-2)=x(2x-3)-x(x-2)
2x^2 -4x = x(2x-3 - x -2)
2x^2 - 7x + 6 = x^2 - x
[tex]x^{2}[/tex] - 6x + 6 = 0
use quadratic equation to get to final answer
-b +- [tex]\frac{-b+\sqrt{b^{2} -4ac } }{2a} , \frac{-b-\sqrt{b^{2} -4ac } }{2a} where a = 1 b = -6 and c= 6[/tex]
