Answer:
The answer is "3"
Step-by-step explanation:
[tex]\to f(7)=f(5 + 2)=1+f(5)\\\\\to f(5)=f(3+2)=1+f(3)\\\\\to f(3)=f(1+2)=1+f(1)=1+0=1\\\\[/tex]
Therefore
[tex]\to f(7)=1+f(5)=1+1+f(3)=2+1+f(1)=2+1+0=3[/tex]
