Answer:
[tex]b^3-c^3=(b-c)(b^2+c^2+bc)[/tex]
Explanation:
We need to write the value of [tex]b ^{3 } - c ^3[/tex]. It is a well known identity of algebra.
[tex]b^3-c^3=(b-c)(b^2+c^2+bc)[/tex]
Here,
b and c are any number.
We know that,
b² = b×b
bc = b × c
Hence, this is the required solution.
