Answer:
[tex]y = - 3[/tex]
Step-by-step explanation:
[tex] \frac{2 log_{10}(y + 5) }{2} = \frac{ log_{10}(20) }{2} - \frac{ log_{10}(5) }{2} [/tex]
[tex] log_{10}(y + 5) = \frac{ log_{10}(20) }{2} - \frac{ log_{10}(5) }{2} [/tex]
[tex]y + 5 = 2 \\ y = - 3[/tex]
