Answer:
Logically that's not possible but if you want to prove it then, you have to use a trick.
Step-by-step explanation:
1 + 1 = 1 + [tex]\sqrt{1}[/tex]
= 1 + [tex]\sqrt{(-1) * (-1)}[/tex]
= 1 + [tex]\sqrt{(-1)}[/tex] * [tex]\sqrt{(-1)}[/tex]
= 1 + [tex]\sqrt{i^2}[/tex] * [tex]\sqrt{i^2}[/tex]
= 1 + i * i
= 1 + i^2
= 1 + (-1)
= 1 - 1
= 0
So, 1 + 1 = 0
Hope this will help. Please give me brainliest.
