Step-by-step explanation:
Given that,
BC = 8
Ac = 15
We can find AB using the pythagoas theorem.
[tex]AB=\sqrt{AC^2+BC^2}\\\\=\sqrt{15^2+8^2}\\\\AB=17[/tex]
We know that,
[tex]\cos\theta=\dfrac{B}{H}[/tex], B is base and H is Hypotenuse
[tex]\cosB=\dfrac{8}{17}[/tex]
Hence, this is the required solution.
