Respuesta :

Trancescient

[tex]x= \pi[/tex]

Step-by-step explanation:

[tex]\cos^2x+\cos x+1=0[/tex]

Let [tex]u= \cos x[/tex]

Then [tex]u^2+2u+1=(u+1)^2=0[/tex]

or

[tex]\cos x = -1[/tex]

This gives us [tex]x= \pi[/tex] or all integer multiples of [tex]\pi (n \pi)[/tex]

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