Answer:
Convert
r
=
8
cos
θ
−
2
sin
θ
to Cartesian form
#x^2 + y^2 - 8 x +2 y = 0, using
r
=
√
x
2
+
y
2
≥
0
and
(
x
,
y
)
=
r
(
cos
θ
,
sin
θ
)
.
The Socratic graph of this circle,
with center at
(
4
,
−
1
)
and radius
√
17
.
is immediate.
graph{(x^2+y^2-8x+2y)((x-4)^2+(y+1)^2-0.04)=0[-1 23 -6 6] }
