9514 1404 393
Answer:
x - 4
Step-by-step explanation:
The expression simplifies to ...
[tex]\sqrt{x^2-8x+16}=\sqrt{(x-4)^2}=|x-4|[/tex]
For x ≥ 4, the argument of the absolute value function is non-negative, so it remains unchanged. The simplified expression is ...
x - 4 . . . . for x ≥ 4
