Given:
Stacked Hay Bales:
L = 1 1/3 feet
W = 4 feet
The volume of each hay bale is equal to 10 2/3 cubic feet
The number of hay bales stacked = 8
To solve for the height, use the volume of the bales and the given length and width of a single bale.
V = l x w x h
10 2/3 cubic feet = 1 1/3 feet * 4 feet * height
height = 2 feet
So, if the height of one bale is 2 feet, then the height of 8 bales stacked is
2 feet * 8 bales = 16 feet
Therefore the height of the stacked hay bales is 16 feet.
