Answer:
Step-by-step explanation:
[tex](\sqrt{14}-\sqrt{3})(\sqrt{12}+\sqrt{7})=\sqrt{14}*\sqrt{12}+\sqrt{14}*\sqrt{7}-\sqrt{3} *\sqrt{12}-\sqrt{3} *\sqrt{7}\\\\=\sqrt{14*12} + \sqrt{14*7}-\sqrt{3*12}-\sqrt{3*7}\\\\=\sqrt{2*7*2*2*3} + \sqrt{2*7*7}-\sqrt{3*3*2*2}-\sqrt{3*7}\\\\=2\sqrt{2*7*3}+7\sqrt{2}-3*2-\sqrt{21}\\\\= 2\sqrt{42}+7\sqrt{2}-6-\sqrt{21}[/tex]
