Respuesta :

Answer:

Explanation:

1 Mole of Aluminum with mass 26.98g contains 6.02*10^23 atoms.

In 2.88g of Aluminum, there are 2.88/26.98*6.02*10^23 = 6.426*10^22 atoms.

Answer:

Explanation:

no of Al atoms = 2.88/26.98*6.02*10^23

= 6.426*10^22

= 6.43*10^22

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