Answer:
The vertex of [tex]f(x) = |x-3| + 6[/tex] is [tex](x,y) = (3, 6)[/tex].
Step-by-step explanation:
The vertex of the absolute value function is the point where [tex]|x-3| = 0[/tex]. Hence, the coordinates of the vertex are, respectively:
[tex]x-3 = 0[/tex]
[tex]x = 3[/tex]
[tex]y = |x-3| + 6[/tex]
[tex]y = |3-3|+6[/tex]
[tex]y = |0|+6[/tex]
[tex]y = 0 + 6[/tex]
[tex]y = 6[/tex]
The vertex of [tex]f(x) = |x-3| + 6[/tex] is [tex](x,y) = (3, 6)[/tex].
