Answer:
36kcal
Explanation:
There are three things that occur in the process not converting ice to steam. They are;
I) fusion of ice
ii) heating of water to 100°C
iii) vaporization of water at 100°C to yield steam
Hence, total heat required to convert ice to steam=
Latent heat of fusion of ice + heat required to raise the temperature of water to 100°C + Latent heat of vaporization of water
Thus;
H= mLfus + mcθ + mLvap
H= m(Lfus + cθ + Lvap)
H= 50(80 + 1(100) + 540)
H= 36000cal
H= 36kcal
