Answer:
8.29g NaCl are present
Explanation:
To solve this question we must, as first, find the moles of NaCl in 260mL of the solution. These moles can be converted to grams using its molar mass (NaCl = 58g/mol)
Moles NaCl:
260mL * (1L / 1000mL) = 0.260L * (0.55mol / L) = 0.143 moles NaCl
Mass NaCl:
0.143 moles NaCl * (58g / mol) = 8.29g NaCl are present
