Answer:
a) the average of change for the number of bacteria from 0 to 6.8 hours is
[tex]the \: average \: of \: change \: = \frac{2292 - 1000}{6.8 - 0} = 190 \: bacteria \: per \: hour[/tex]
b)
[tex]the \: average \: rate\: of \: change \: from \: 10.2 \: to \: 13.6 \: hours \: = \frac{5080 - 3856}{13.6 - 10.2} = 360[/tex]
