Answer:
5.875 g of Oxygen
Explanation:
We must first balance our decomposition equation KClO3 -> K + ClO3
The amount of oxygen in CLO3 is 3 times the original. We begin by converting 15g of KClO3 to moles. 15 / (39.1 + 35.45 + 3(16) ) = 0.122 mols.
Then we go to moles of oxygen,
.122 * 3 = 0.367 mols of Oxygen
Then to grams of Oxygen
.367 * 16 = 5.875 g
