emma7823 emma7823
  • 19-05-2021
  • Mathematics
contestada

Whenever w is an integer greater than 1, logw w^2/w^6=?
-4
-3
-1/3
1/3
3

Whenever w is an integer greater than 1 logw w2w6 4 3 13 13 3 class=

Respuesta :

eudora eudora
  • 24-05-2021

Answer:

Option (1)

Step-by-step explanation:

Given expression is,

[tex]\text{log_w(\frac{w^2}{w^6})}[/tex][tex]\text{log}_w(\frac{w^2}{w^6} )[/tex]

Let the given expression is equal to y.

[tex]\text{log}_w(\frac{w^2}{w^6} )=y[/tex]

By applying logarithmic rule,

[tex](\frac{w^2}{w^6} )=w^y[/tex]

[tex]w^2\times w^{-6}=w^y[/tex]

[tex]w^{2-6}=w^y[/tex]

[tex]w^{-4}=w^y[/tex]

[tex]y=-4[/tex]

Therefore, value of the given expression [tex]\text{log}_w(\frac{w^2}{w^6} )=-4[/tex].

Option (1) will be the correct option.

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