Answer: [tex]1.089\times 10^5\ A[/tex]
Explanation:
Given
Charge discharged [tex]Q=9.7\C[/tex]
time taken [tex]t=8.9\times 10^{-5}\ s[/tex]
Current is given as rate of change of discharge i.e.
[tex]\Rightarrow I=\dfrac{Q}{t}\\\\\Rightarrow I=\dfrac{9.7}{8.9\times 10^{-5}}\\\\\Rightarrow I=1.089\times 10^5\ A[/tex]
Therefore, the average current is [tex]1.089\times 10^5\ A[/tex]
