Answer:
[tex]fro \: the \: equation : \\ 6 \: moles \: of \: nitric \: acid \: produce \: 2 \: moles \: of \: water \\ 1.1 \: moles \: of \: nitric \: acid \: react \: with \: ( \frac{1.1}{6} \times 2) \: moles \\ = 0.367 \: moles \: of \: water \\ 1 \: mole \: of \: water \: weighe \: 18 \: g \\ 0.367 \: moles \: will \: weigh \: ( 0.367 \times 18) \: g \\ = 6.6 \: g \: of \: water[/tex]
