Answer:
See below
Step-by-step explanation:
ΔABC has been flipped over, so we have a reflexion using line BC
So, the answer to 1. is line BC
The result is ΔE'F'D'
Now ΔE'F'D' is moved 4 units to the right. That is the answer to 2.
The result is ΔE"F"D"
Finally ΔE"F"D" is moved 1 unit down. That is the answer to 3.
The final result is ΔEFD
Ok. Did that help you?
