Answer:
[tex]108\pi[/tex] inches³
Step-by-step explanation:
Hi there!
[tex]V=\frac{1}{3} \pi r^2h[/tex] where r is the radius and h is the height
Plug in the given values (r=6, h=9)
[tex]V=\frac{1}{3} \pi (6)^2(9)\\V=\frac{1}{3} \pi (36)(9)\\V=\frac{1}{3} \pi (324)\\V=108\pi[/tex]
Therefore, the volume of the cone is [tex]108\pi[/tex] inches³.
I hope this helps!
