Answer: [tex]\frac{2}{3}[/tex]
Step-by-step explanation:
Given
Angelo drew a model with his drawing length 10 inches tall
The actual pole length is 15 feet tall
drawing scale is the ratio of drawing length to the actual length i.e.
[tex]\Rightarrow \text{Scale used l=}\dfrac{10}{15}\\\\\Rightarrow l=\dfrac{2}{3}[/tex]
