Answer:
when x>2 (x= 3)
f(x) = -(x-2)² +1
when x = 3
f(3) = -(3-2)²+1
f(3) = -(-1)²+1
f(3) = -1+1
f(3) = 0
taking lesser value of x
makes f(x) increase
and when x>1
(x=2)
Now let's take x = 2
f(2) = -(2-2)²+1
f(2)= -(0)²+1
f(2)= 0+1 = 1
Therefore the values of x that makes f(x) = -(x-2)²+1 to increase are are (x>2 and x>1)
