Answer:
[tex]\huge\boxed{x \geq \frac{10b}{b-a} }[/tex]
Step-by-step explanation:
[tex]\displaystyle b(x-3) \geq ax+7b\\\\bx -3b\geq ax+7b\\\\Subtract \ ax \ to \ both \ sides\\\\bx-ax-3b\geq 7b\\\\Add \ 3b \ to \ both \ sides\\\\bx-ax \geq 7b+3b\\\\x(b-a) \geq 10b\\\\Divide \ (b-a) \ to \ both \ sides\\\\x \geq \frac{10b}{b-a} \\\\\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807
