Answer:
[tex]g = 6 \sqrt{3} \\ f = 6[/tex]
Step-by-step explanation:
[tex] \sin(60) = \frac{g}{12} = \frac{ \sqrt{3} }{2} \\g = \frac{12 \times \sqrt{3} }{2} = 6 \sqrt{3} \\ f = \sqrt{12 ^{2} - {6 \sqrt{3} }^{2} } = 6[/tex]
