Answer:
[tex](\dfrac{1}{4})^{\dfrac{-3}{2}}[/tex] = 8
Step-by-step explanation:
The given expression is :
[tex](\dfrac{1}{4})^{\dfrac{-3}{2}}[/tex]
We know that,
[tex]\dfrac{1}{x}=x^{-1}[/tex]
So,
[tex](\dfrac{1}{4})^{\dfrac{-3}{2}}=(\dfrac{1}{2^2})^{\dfrac{-3}{2}}\\\\=(2^{-2})^{\dfrac{-3}{2}}\\\\=(2^{-1})^{-3}\\\\=2^3\\\\=8[/tex]
So, the value of the given expression is 8.
