Answer:
[tex] \frac{4}{5} [/tex]
Step-by-step explanation:
[tex] ( \cos \theta) ^{2} + ( \sin \theta) ^{2} = 1 \\ \\ \therefore \: { \bigg( \frac{{6} }{10} \bigg)}^{2} + ( \sin \theta) ^{2} = 1 \\ \\ \frac{36}{100} + ( \sin \theta) ^{2} = 1 \\ \\ ( \sin \theta) ^{2} = 1 - \frac{36}{100} \\ \\ ( \sin \theta) ^{2} = \frac{100 - 36}{100} \\ \\ ( \sin \theta) ^{2} = \frac{64}{100} \\ \\ \sin \theta = \sqrt{\frac{64}{100} } \\ \\ \sin \theta = \frac{8}{10} \\ \\ \sin \theta = \frac{4}{5} [/tex]
