addiemaygulley6007 addiemaygulley6007
  • 17-05-2021
  • Chemistry
contestada

2Fe +3S= Fe2S3 how many grams of sulfur are involved in this reaction if 95 grams of iron are needed to react with sulfur

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dsdrajlin
dsdrajlin dsdrajlin
  • 19-05-2021

Answer:

83 g

Explanation:

Step 1: Write the balanced equation

2 Fe + 3 S ⇒ Fe₂S₃

Step 2: Calculate the moles corresponding to 95 g of Fe

The molar mass of Fe is 55.85 g/mol.

95 g × 1 mol/55.85 g = 1.7 mol

Step 3: Calculate the moles of S needed to react with 1.7 moles of Fe

The molar ratio of Fe to S is 2:3. The moles of S needed are 3/2 × 1.7 mol = 2.6 mol

Step 4: Calculate the mass corresponding to 2.6 moles of S

The molar mass of S is 32.07 g/mol.

2.6 mol × 32.07 g/mol = 83 g

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