Answer:
we have
secθ = 2
[tex] \frac{1}{cos θ} [/tex]=2
Cosθ =[tex] \frac{1}{2 }[/tex]
[tex] \frac{b}{h }=\frac{1}{2 }[/tex]
b=1
h=2
p=[tex] \sqrt{2²-1} = \sqrt{3} [/tex]
again
Cot θ=[tex] \frac{b}{p }[/tex]
Cot θ=[tex] \frac{1}{ \sqrt{3}} [/tex]
Cot θ=[tex] \frac{\sqrt{3}}{3} [/tex]
It lies in Quadrant III cot is positive
Cot θ=[tex] \frac{\sqrt{3}}{3} [/tex]
b. (sqrt 3)/3
