Respuesta :

coolunnameduser

[tex]a^{-n} = \frac{1}{a^n}[/tex]

[tex](6^{-1} + (3-2)^{-1})^{-1} = (\frac{1}{6} + \frac{1}{3-2})^{-1} = (\frac{1}{6} + \frac{1}{1})^{-1} = (\frac{7}{6})^{-1} = \frac{6}{7}[/tex]

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