Answer:
[tex]t=\sqrt{\dfrac{2s}{a}}[/tex]
Step-by-step explanation:
The given equation is :
[tex]s=ut+\dfrac{1}{2}at^2[/tex]
Where
s is displacement
u is the initial velocity
a is acceleration
t is time
If u = 0, the above equation become,
[tex]s=\dfrac{1}{2}at^2\\\\t^2=\dfrac{2s}{a}\\\\t=\sqrt{\dfrac{2s}{a}}[/tex]
Hence, the value of t is equal to [tex]\sqrt{\dfrac{2s}{a}}[/tex].
