Answer:
[tex]\displaystyle 10 = x[/tex]
Step-by-step explanation:
[tex]\displaystyle a^2 + b^2 = c^2 \\ \\ 8^2 + 6^2 = x^2 \hookrightarrow 64 + 36 = x^2 \hookrightarrow \sqrt{100} = \sqrt{x^2} \\ \\ \boxed{10 = x}[/tex]
We only want the NON-NEGATIVE root sinse we are measuring the length of the hypotenuse.
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