Answer:
See below
Step-by-step explanation:
[tex]y = {u}^{ \frac{3}{2} } \\ \\ \therefore \: \frac{dy}{du} = \frac{3}{2} {u}^{ \frac{3}{2} - 1 } = \boxed{\frac{3}{2} {u}^{ \frac{1}{2}} } \\ \\ u = 8x + 3 \\ \\ \frac{du}{dx} = 8.1 + 0 = \boxed{8}[/tex]
