0.161 mols.
Balance the equation first
2Fe + O2 •••••> 2FeO
Find the molar masses of the compound
2(56) + 2(16) •••••> 2(56+16)
112g + 32g •••••> 144g
Fe reacting with O2
112g of Fe reacting with 32g of O2
18g of Fe reacting with x
x= 32×18/112
x= 5.143g
Amount= mass/ molar mass
Amount= 5.143g/32g
Amount= 0.161mls
