Answer:
Step-by-step explanation:
(2x^2 + 10x + 7x + 35) - (x^2 - 3x + 5x - 15)
x^2 + 15x + 50
(x + 5)(x + 10)
x = -10
a
(x+5)(2x+7)-(x+5)(x-3)
factorize (x+5) out
(x+5)[(2x+7)-(x-3)]
(x+5)(2x+7-x+3)
(x+5)(2x-x+7+3)
(x+5)(x+10)
b. to get the zeros of the equation,
(x+5)(x+10)=0
x+10=0
x=-10
since the other one has been found already
