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Answer:

10 moles of S₈

320 moles O₂

Explanation:

  • S₈ +O₂ → SO₈

The balanced equation is:

  • S₈ + 32O₂ → 8SO₈

Now we can convert moles of SO₈ (the product) into moles of each reactant, using the stoichiometric coefficients of the balanced reaction:

  • 80 mol SO₈ * [tex]\frac{1molS_8}{8molSO_8}[/tex] = 10 mol S₈
  • 80 mol SO₈ * [tex]\frac{32molO_2}{8molSO_8}[/tex] = 320 mol O₂

In order for 80 moles of SO₈ to be produced, 10 moles of S₈ need to react with 320 moles of O₂.

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