Answer:
[tex]n(A \cup B) = 6[/tex]
Step-by-step explanation:
In Venn sets, we have that:
[tex]n(A \cup B) = n(A) + n(B) - n(A \cap B)[/tex]
In which n is the number of elements that each set contains.
In this question:
[tex]n(A) = 8, n(B) = 9, n(A \cap B) = 6[/tex]
So
[tex]n(A \cup B) = n(A) + n(B) - n(A \cap B) = 8 + 9 - 6 = 17 - 6 = 11[/tex]
So
[tex]n(A \cup B) = 6[/tex]
