Answer:
lesser [tex]x=-8-\sqrt{2}=-9.41[/tex]
greater [tex]x=-8+\sqrt{2}=-6.59[/tex]
Step-by-step explanation:
[tex](x+8)^2-2=0\\(x+8)^2=2\\x+8=\pm\sqrt{2}\\x=-8\pm\sqrt{2}\\[/tex]
This means that
lesser [tex]x=-8-\sqrt{2}=-9.41[/tex]
greater [tex]x=-8+\sqrt{2}=-6.59[/tex]
