Answer:
[tex]E = 2.9775\times10^5 J[/tex]
Explanation:
Given: The latent heat of fusion for Aluminum is [tex]L = 3.97\times10^5 J/Kg[/tex]
mass to be malted m = 0.75 Kg
Energy require to melt E = mL
[tex]E = 3.97\times10^5\times0.75 = 2.9775\times10^5 J[/tex]
Therefore, energy required to melt 0.75 Kg aluminum
[tex]E = 2.9775\times10^5 J[/tex]
