Answer:
The amount of HI is "64 grams".
Explanation:
The given values are:
Volume,
= 0.500 L
Molarity,
= 1.00 H
Molar mass of HI,
= 128
Now,
The moles of HI will be:
= [tex]Molarity\times Volume[/tex]
On substituting the values, we get
= [tex]1.00\times 0.500[/tex]
= [tex]0.5 \ mol[/tex]
hence,
The amount of HI will be:
= [tex]Moles\times Molar \ mass[/tex]
= [tex]0.5\times 128[/tex]
= [tex]64 \ grams[/tex]
