Answer:
106
Step-by-step explanation:
this question represents an arithmetic sequence problem where you can use this formula: a(n) = a(1) + d(n-1) where 'n' is value you're solving for, a(1) is the initial value, and 'd' is the common difference
a(20) = 49 + 3(20-1)
= 49 + 3(19)
= 49 + 57
= 106
