Answer:
Volume of 6.5 moles of Helium at STP is 145.6954 L
Explanation:
As we know
[tex]pV = nRT[/tex]
At STP, temperature is 273.15 K and pressure is 1 atm
n is the number of moles which is equal to 6.5
R is the gas constant = 0.08206 L atm/K mol
Substituting the given values in above equation, we get -
[tex]1 * V = 6.5 * 0.08206 * 273.15\\V = 145.6954[/tex]Liters
Volume of 6.5 moles of Helium at STP is 145.6954 L
