Answer:
m = 49.8 g
Explanation:
Hello there!
In this case, for this calorimetry processes we can define the involved heat in terms of mass, specific heat and temperature as shown below:
[tex]Q=mC\Delta T[/tex]
Thus, given the heat, final and initial temperature and specific heat of water (4.184), the mass of water can be computed as shown below:
[tex]m=\frac{Q}{C\Delta T}\\\\m=\frac{12500J}{4.184\frac{J}{g\°C}(75\°C-15.0\°C)} \\\\m=49.8g[/tex]
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