Answer:
[tex] \boxed{A. \: 134 \: in³} [/tex]
Explanation:
Volume of a cone: ⅓πr²h.
Where r is the radius, and h is the height.
The diameter is twice (2 times) the radius.
(⅓)(π)(4²)(16) – (⅓)(π)(4²)(8) =
256 / 3 π – 128 / 3 π =
128 / 3 π =
42 ⅔ π = 134.041287... ≈ 134 in³
