Sucio0990 Sucio0990
  • 20-03-2014
  • Mathematics
contestada

Solve for x: log6x-log2=1

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HannahN HannahN
  • 20-03-2014
Log(6x/2)=1
Log(3x)=1
This is the same as saying 10^1=3x
10=3x
x=10/3 or 3 and 1/3
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Аноним Аноним
  • 22-03-2014
[tex]log6x-log2=1;\ D:6x > 0\to x > 0\to x\in\mathbb{R^+}\\\\log6x-log2=1\\\\log\left(6x:2\right)=log10^1\\\\3x=10\ /:3\\\\x=\frac{10}{3}\\\\x=3\frac{1}{3}\in D[/tex]


[tex]a > 0\ \wedge\ b > 0\ \wedge\ c > 0\ \wedge\ d\in\mathbb{R}\\\\log_ab-log_ac=log_a(b:c)\\\\log_ab=d\iff\ a^d=b\ \ (log_ab=log_aa^d)[/tex]
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